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  1. Do you have api to calculate Brokerage fees

    rakeshr
    by rakeshr · November 2020
    No, currently we don't have. Maybe you can create this functionality at your end, you can check the complete charge here. Or use the Zerodha brokerage calculator.
  2. Kite Connect API - Update

    Gopikrishnan
    by Gopikrishnan · September 2020
    Also adding APIs for brokerage cost calculations will be very useful particularly for options trading. These are very complex otherwise https://zerodha.com/brokerage-calculator#tab-equities
  3. Brokerage calculator

    rakeshr
    by rakeshr · July 2020
    @rmishra258
  4. order placing Exceptions

    rakeshr
    by rakeshr · July 2020
    @pawan12
  5. Order placed on NSE executed on BSE

    rakeshr
    by rakeshr · June 2020
    @vijoeyz So, do I calculate my trading cost as per https://zerodha.com/charges#tab-equities ? There are no additional charges buying on one exchange and selling on another?
  6. Order placed on NSE executed on BSE

    vijoeyz
    by vijoeyz · June 2020
    So, do I calculate my trading cost as per https://zerodha.com/charges#tab-equities ? There are no additional charges buying on one exchange and selling on another?
  7. Clarity on Options Order Execution costs

    jkrise
    by jkrise · October 2019
    For options trading, the costs as per link https://zerodha.com/brokerage-calculator#tab-equities seem to be invalid. Actual costs are way higher than presented,even after taking into consideration sta
  8. Get trade reports for trades only places through APIs

    rakeshr
    by rakeshr · November 2018
    @hardik__ Is there a way to bifurcate orders in kite's dashboard on the basis of source of the order ?
  9. Is there a way to differentiate app based orders vs. web based orders

    rakeshr
    by rakeshr · July 2018
    @avinashcherukuri
  10. A Simple Python Function to Detect Support/Resistance Levels

    charuvindatre
    by charuvindatre · January 2017
    />ltp_s = smooth(ltp, (n+1), 3) <br />#taking a simple derivative<br />ltp_d = np.zeros(n_ltp)<br />ltp_d[1:] = np.subtract(ltp_s[1:], ltp_s[:-1])<br />resistance = []<b
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