How to Close Web Socket?

@sujith :

Close method has been called inside forloop.


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from kiteconnect import KiteConnect
from kiteconnect import KiteTicker

# Initialise
kite = KiteConnect(api_key)
kite.set_access_token(access_token)
kws = KiteTicker(api_key, access_token)


def on_ticks(ws, ticks):
    for tick in ticks:  
        # want to exit on condition of after 3:30	
        ws.close()
	
	
def on_close(ws, code, reason):
    # On connection close stop the main loop
    # Reconnection will not happen after executing `ws.stop()`
    ws.stop()

		
# Callback for successful connection.
def on_connect(ws, response):
	ws.subscribe(token_list)
	ws.set_mode(ws.MODE_FULL, token_list)	
	#ws.set_mode(ws.MODE_LTP, tokens)	
	

# Assign the callbacks.
kws.on_ticks = on_ticks
kws.on_connect = on_connect
kws.on_close = on_close
# Infinite loop on the main thread. Nothing after this will run.
# You have to use the pre-defined callbacks to manage subscriptions.
# kws.connect(threaded=True)
kws.connect()

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@babansfolio Closing websocket inside for loop is wrong. This is pretty straightforward thing. You can simply compare if datetime is post 3:30, call `ws.close()` inside on_ticks.

is there a way the socket can be closed in console?

I have been using the above logic (last 4 lines, the last line, 'raise SystemExit' is what I use, you guys can write whatever you need) to disconnect the WebSocket connection successfully. The given logic has an advantage over the kws.on_close call, let me share that from my experience:

If the on_close function is defined in your code then if anytime due to any reason connection is lost or interrupted due to network issues then the on_close call gets triggered and Websocket will stop running. Instead if you use the above logic to close the WebSocket connection then your connection also gets closes neatly and also if ever there is network interruption then the WebSocket will keep waiting till network connection is re-established and your code will not break.

If any clarification is required, feel free to drop me a mail at: [email protected] / [email protected]

Go through the WebSocket streaming FAQs here.