☰
Login
Signup
Home
›
Python client
Howdy, Stranger!
It looks like you're new here. If you want to get involved, click one of these buttons!
Sign In
Register
Categories
Recent Discussions
Activity
Categories
13.8K
All Categories
0
Incidents
154
Node JS client
40
Go client
793
.Net API client
378
Kite Publisher
537
.Net / VBA / Excel (3rd party)
457
Algorithms and Strategies
993
Java client
1.1K
API clients
404
PHP client
4K
Python client
346
Mobile and Desktop apps
1.4K
Market data (WebSockets)
3.3K
General
In this Discussion
January 4
sujith
January 4
VijayJoy
January 4
MAG
Login issue
VijayJoy
January 4
in
Python client
Hi,
From today I am not able to connect to the web socket servers, getting 403 below is the error.
Error:
2024-01-04 10:58:41+0530 [-] failing WebSocket opening handshake ('WebSocket connection upgrade failed (403 - Forbidden)')
2024-01-04 10:58:41+0530 [-] dropping connection to peer tcp4:13.126.69.37:443 with abort=True: WebSocket connection upgrade failed (403 - Forbidden)
2024-01-04 10:58:41+0530 [-] will retry in 2 seconds
2024-01-04 10:58:41+0530 [-] Stopping factory
2024-01-04 10:58:44+0530 [-] Starting factory
2024-01-04 10:58:44+0530 [-] failing WebSocket opening handshake ('WebSocket connection upgrade failed (403 - Forbidden)')
2024-01-04 10:58:44+0530 [-] dropping connection to peer tcp4:13.126.69.37:443 with abort=True: WebSocket connection upgrade failed (
Regards,
Vijay
Tagged:
login error
MAG
January 4
403 forbidden is an access denied error. Has your api app subscription expired or are you using an expired access token?
VijayJoy
January 4
Yes it is with access token after getting a new one issue is solved, btw how long access token is valid and what is the expiry time?
VijayJoy
January 4
Is there a way to get access token without the extra authentication code (as it require manual intervention)?
sujith
January 4
An access token is valid for one whole day once created. Unless you call generate access token again or call logout or do master logout from Kite web.
Sign In
or
Register
to comment.