How to close and connect the websocket purposely

Dileep

Hi .. Any one kindly help me.. In between the market hours i want to close and connect to the websocket. Below is the sample code.
def on_ticks(ws,ticks):
//Some logic
kws.close()
time.sleep(1)
kws.connect()

def on_connect(ws, response):
ws.subscribe(Tokens)
ws.set_mode(ws.MODE_FULL,Tokens)

kws.on_ticks = on_ticks
kws.on_connect = on_connect
kws.connect()

But sometimes in between i am getting the error as "429 - TooManyRequests". How to avoid this error. Is there is any way to cleanly close the connection?
Thanks in advance.

sujith

You can call this method to close the Websocket connection.

Dileep

Hi @sujith thanks for the response. PFA. Is this is the correct way.Please guide me if i need to modify anything.

Dileep

Hi @sujith @rakeshr after implementing above code still getting the error as

kiteconnect.ticker - ERROR - Connection error: 1006 - connection was closed uncleanly (WebSocket closing handshake timeout (peer did not finish the opening handshake in time))

Can you advise me to close the connection gracefully.

ANL

I cant understand why you put kws.stop() , kws.conect() inside on_ticks() ?
Don't put any tick calculations inside on_ticks() it will block your ticks if you do that.

try this:
def on_close(ws, code, reason):
ws.stop()

Include this thread when connecting with the kite ticker , kws.connect(threaded=True) instead of just kws.connect()