request token error

YBZ170

I am entering the correct request token, within a minute. I am still receiving the error "TokenException: Token is invalid or has expired."

I bought the api two days back and received the api key and api secret the same day. but the amount for my api and historical api deducted today.

rakeshr

"TokenException: Token is invalid or has expired."

Are you still facing issue?
Go through the login FAQs here.

YBZ170

I went through the FAQ, I get an error 403. I am entering the request token within a minute, have tried in multiple times and ensured that I am entering correct details. I have a question regarding the subscription too, is it possible to get api key and secret without amount getting deducted from my kite trading app?

sujith

Nope, You need a Kite Connect app to create a session. You might have created a Kite Publisher app.

YBZ170

can you share a sample login code, so that i can check ?

YBZ170

this is the basic structure of what I'm using

from kiteconnect import KiteConnect
import webbrowser

api_key = " "
api_secret = " "

# Initialize KiteConnect
kite = KiteConnect(api_key=api_key)

# Generate login URL and open it in a browser
login_url = kite.login_url()
print(f"Login URL: {login_url}")

# Open the login URL in the browser
webbrowser.open(login_url)

# Prompt the user to enter the request token
request_token = input("Enter the request token: ").strip()

# Debugging: print the request token to ensure it's correct
print(f"Request Token: {request_token}")

try:
# Generate access token using the request token and API secret
data = kite.generate_session(request_token, api_secret)
access_token = data["access_token"]
print(f"Access Token: {access_token}")

# Initialize the KiteConnect object with the access token
kite.set_access_token(access_token)

# Make API calls
profile = kite.profile()
print(profile)
except Exception as e:
print(f"Error: {e}")

sujith

It is mandatory by the exchange that a user has to login manually at least once day. We don't recommend automating login.